Answer by WA Don for Convergence of this series through comparison
Match pairs of terms in the numerator and denominator, writing,\begin{align}\frac{(n!)^2}{(2n)!} = \left(\frac{n}{2n}\cdot\frac{n-1}{2n-2}\cdots\frac{1}{2}\right)\cdot\left(\frac{n}{2n-1}\cdot...
View ArticleConvergence of this series through comparison
How can I give some estimation of the convergence of this series, only using comparison and majorisation of the terms?$$\sum_{n = 0}^{+\infty} \frac{(n!)^2}{(2n)!}$$I tried with$$(n!)^2 = n^2\cdot...
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